Tanya Skrip agar langsung Mengambil gambar dan Menyimpan data ke database
ciampeaudik bogor · May 17, 2013
Bro Ellyx ane kan pakai plugin jpeqcam ()
ini halaman index nya :
Tombol untuk mengambil gambar nya ada pada
<input type=button value="Take Snapshot" onClick="take_snapshot()">
Nah bagaimana agar ketika halaman ini di load langsung melakukan "take_snapshot()"
dan menyimpan gambar tersebut pada database mysql nya, bukan pada sebuah folder.
Please mas Ellyxxx..
ini halaman index nya :
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>JPEGCam Test Page</title>
<meta name="generator" content="TextMate http://macromates.com/">
<meta name="author" content="Joseph Huckaby">
<!-- Date: 2008-03-15 -->
<!-- First, include the JPEGCam JavaScript Library -->
<script type="text/javascript" src="webcam.js"></script>
<!-- Configure a few settings -->
<script language="JavaScript">
webcam.set_api_url( 'test.php' );
webcam.set_quality( 90 ); // JPEG quality (1 - 100)
webcam.set_shutter_sound( true ); // play shutter click sound
</script>
<!-- Next, write the movie to the page at 320x240 -->
<script language="JavaScript">
document.write( webcam.get_html(320, 240) );
</script>
</head>
<body>
<table><tr><td valign=top>
<h1>JPEGCam Test Page</h1>
<h3>Demonstrates a very simple, one-click capture & upload implementation</h3>
<!-- Some buttons for controlling things -->
<br/><form>
<input type=button value="Configure..." onClick="webcam.configure()">
<input type=button value="Take Snapshot" onClick="take_snapshot()">
</form>
<!-- Code to handle the server response (see test.php) -->
<script language="JavaScript">
webcam.set_hook( 'onComplete', 'my_completion_handler' );
function take_snapshot() {
// take snapshot and upload to server
document.getElementById('upload_results').innerHTML = '<h1>Uploading...</h1>';
webcam.snap();
}
function my_completion_handler(msg) {
// extract URL out of PHP output
if (msg.match(/(http\:\/\/\S+)/)) {
var image_url = RegExp.$1;
// show JPEG image in page
document.getElementById('upload_results').innerHTML =
'<h1>Upload Successful!</h1>' +
'<h3>JPEG URL: ' + image_url + '</h3>' +
'<img src="' + image_url + '">';
// reset camera for another shot
webcam.reset();
}
else alert("PHP Error: " + msg);
}
</script>
</td><td width=50> </td><td valign=top>
<div id="upload_results" style="background-color:#eee;"></div>
</td></tr></table>
</body>
</html>
Tombol untuk mengambil gambar nya ada pada
<input type=button value="Take Snapshot" onClick="take_snapshot()">
Nah bagaimana agar ketika halaman ini di load langsung melakukan "take_snapshot()"
dan menyimpan gambar tersebut pada database mysql nya, bukan pada sebuah folder.
Please mas Ellyxxx..